Guzheng sellers often caution against using the wrong string in the wrong location on your instrument. “Things get too tight” they say “the strings will snap”. Okay, sure, we’ve all seen or heard of a string snapping, and most everyone will snap a string themselves at some point. But what kind of numbers are we talking about? I investigated and it turns out: a lot. A typical guzheng holds around 800 pounds of force on its strings (360kg)! That’s like a group of people just standing on your instrument. That’s huge!
I also investigated how much tension increases when you force a string too high. Well - A normal #2 string tuned to B5 would experience a tension of around 15 pounds (7 kg). But push that just two strings higher, to D6, and it sits at 20 pounds. That’s a 30% increase! E6 on the same string would demand 25 pounds, or 60% beyond design!
The bass strings are even scarier. A happy #21 string is already at ~60 pounds force (26kg). To push that two notes higher to G2 without moving the bridge you would need 120 POUNDS of force on that string.
This is why tuning distances and strings are important. Explore below to see the math of how I did it.
We need math and we need measurements. The math for this comes from the Mersenne-Taylor formula:
F = frequency (such as 440 Hz)
L = The length of the string that is vibrating
T = tension
and µ = mass per unit length.
Rearrange the Equation
We want to get T, tension, by itself and everything else on the other side of the equals sign. Doing some quick algebra we get:
If our strings are made only of drawn wire as used to be the case, we can use an equation like this:
The first three terms are the surface area of the cross section of the wire, assuming it is a perfect circle.
π = the constant pi, 3.14159….
d = diameter of the string, measured from the steel wire in question using calipers. Then:
ρ = density of the material. If we are just looking at steel-string guzheng then ~7.8 g/cm3 works for steel.
Unfortunately modern guzheng use multi-layered, multi-material strings. The core is steel, then sometimes wound in copper, then wound in 2 layers of nylon thread or silk, and then wound in thicker nylon “wire”. So, we need to get the mass-per-unit-length of each of the materials, then combine them into one value. To get the mass per unit length, we need surface area for each.
Calculate Mass per Length using Surface Area
We need surface area for the steel, copper, and then the nylon and thread.
The above equation works for the steel core, so that’s straightforward. Unwinding the guzheng strings I measured the steel core and wrote it down.
The density is for steel, 7.8 g/cm3
I measured the diameter of the copper winding directly, but sometimes it is ribbon and sometimes, round wire. To keep the math reasonable I assumed it was always perfectly round wire. Sine the copper is wound around the steel core and is a constant diameter we can treat its cross section like a ring:
R = the outer radius of the ring (steel + copper)
r = the inner radius of the ring (steel)
ρ = density of copper. I used an approximate density for a copper alloy, 8.8g/cm3, because copper alloys tend to be cheaper than pure copper.
Nylon and Thread:
Here I have to make another assumption - that the nylon wrapping and thread have the same density, and that they make up the rest of the diameter of the string. We again need to do the ring equation, but this time we’re using different values for the radii.
The inner radius is made of half the steel core diameter and the whole diameter of the cop\per - because the copper winds around both sides of the core.
Put these into the earlier mass per unit length for rings, and use the density of nylon, ~ 1g/cm3. You should now have three mass-per-unit-lengths, one for each material.
Sum the values together and now you have the mass per length for a given section of modern guzheng wire.
Find the Tension
Now we can bring the mass per length value back into the Tension equation.
L = the length of the string that vibrates. That’s only the distance between the tip of the right fixed bridge and the movable bridge for that string. We don’t factor in the left side of the instrument.
F = the frequency or note that the string emits.
Run this equation for each of the 21 strings and you get a tension in g/s2, or dynes. Convert that to pounds-force or Kilograms-force and you get: around 800 pounds force!